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目的探讨植物纤维素降解最佳培养基成分配比。方法以稻草粉为培养基质,接种黑曲霉进行固体发酵,以发酵产物-还原糖为标准,不同的氮源(浓度为2%的氯化铵、硝酸铵、硫酸铵、蛋白胨、酵母浸膏)、金属离子(2×10-3mol/L的Fe~(2+)、Fe~(3+)、Ca~(2+)、Na~+、Mg~(2+)、K~+)、表面活性剂(0.1%的Tween-60、Tween-80、Tween-100及SDS)进行优化配比,并通过正交设计加以验证。结果最佳发酵培养基成分为稻草粉100 g、(NH_4)_2SO_42 g、MgSO_4·7H_2O0.05 g、KH_2PO_40.1 g、Tween-80 0.1%、水200 ml、自然p H值。结论优化后的稻草固体糖化发酵培养基,可使发酵产物最大化,促进植物纤维素的开发利用。
Objective To explore the optimum proportion of plant cellulose degradation medium. Methods Rice straw as substrate was inoculated with Aspergillus niger for solid fermentation. Fermentation product - reducing sugar was used as the standard. Different nitrogen sources (ammonium chloride, ammonium nitrate, ammonium sulfate, peptone, yeast extract) , Metal ions (2 × 10-3mol / L Fe 2+, Fe 3+, Ca 2+, Na +, Mg 2+, K +), The active agents (0.1% Tween-60, Tween-80, Tween-100 and SDS) were optimized and validated by orthogonal design. Results The optimum fermentation medium consisted of 100 g of straw powder, (NH 4) 2 SO 4 2 g, MgSO 4 4.7H 2 O 0.05 g, KH 2 PO 4 O.l g, Tween-80 0.1%, water 200 ml and natural p H value. Conclusion The optimized straw solid saccharification and fermentation medium can maximize the fermentation products and promote the development and utilization of plant cellulose.