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笔者发现并证明了函数y=Aax+BCax+D(AD-BC≠0,CD≠0)图像的对称中心为(loga|DC|,AD+BC2CD),现将探究的全过程表述如下.1问题的起源高中数学中有二个常见的例题:例1证明函数f(x)=2x+12x-1为奇函数.例2已知f(x)=12x+2,求f(-4)+f(-3)+…+f(5)+f(6)的值.从例1可以得出函数f(x)=2x+1
The author finds and proves that the symmetry center of the function y=Aax+BCax+D (AD-BC≠0, CD≠0) is (loga|DC|,AD+BC2CD). The whole process of the inquiry is described as follows.1 The origin of the problem There are two common examples in high school mathematics: Example 1 proves that the function f(x) = 2x + 12x-1 is an odd function. Example 2 It is known that f(x) = 12x + 2 and find f(-4) The value of +f(-3)+...+f(5)+f(6). It can be derived from Example 1 that the function f(x)=2x+1