论文部分内容阅读
直接求解不等式问题困难较大时,可适当的将原式拆、添、配,运用此技巧便可化难为易,化繁为简,提高解题速度,激发学生的数学学习兴趣.本文举例加以说明. 1.拆的技巧例1 求y=x2+(3/x)(x>0)的最小值. 分析:本题是利用基本不等式求最值的问题,而应用a+b+c≥3 3(abc)求最值时,应考虑到三个正数的积(和)为常数,且三数相等时它们的和(积)取最小(大)值.因此需将3/x平均拆
When it is difficult to directly solve inequality problems, it can be appropriately dismantled, added, and matched. Using this technique, it can be difficult to make it easier, simplify and simplify, increase the speed of problem solving, and stimulate students’ interest in mathematics learning. Instructions. 1. Disassembly techniques Example 1 Find the minimum value of y=x2+(3/x)(x>0). Analysis: This question is to use the basic inequality to find the best value, and apply a+b+c≥3 3 (abc) When finding the best value, consider that the product of the three positive numbers (and) is a constant, and that the sum (product) of the three numbers is equal to the smallest (large) value. Therefore, the 3/x average must be removed