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题目已知函数f(x)=xlnx/(x+1)和直线l:y=m(x-1),若对任意的x∈[1,+∞),f(x)≤m(x-1)恒成立,求m的取值范围;以上是2016年湖北省三月联考数学(理科)第22题,以下给出的三种解法体现了解决含参恒成立问题的三种基本策略.解法1(分离参数)
The problem is that the function f (x) = xlnx / (x + 1) and the line l: y = m -1) constant established, seeking m range of values; The above is 2016 Hubei province March entrance exam mathematics (science) 22 questions, the following three solutions are reflected to solve the problem of three parameters Strategy. Solution 1 (separation parameters)