高中物理甲种本第一册明确指出;从匀变速运动的速度图象可以求出加速度。在图1所示的速度图象中,用△t 表示t_2-t_1,用△v 表示 v_2-v_1,直线 AB 的斜率 k 为 k=△v/△t=a这就是说,匀变速直线运动的速度图线的斜率等于运动物体的加速度。由数学可知:直线1(如图2所示)向上的方向与 x 轴的正方向所成的最小正角叫做这条直线的倾斜角。倾斜角不是90°的直线,它的倾斜角的正切叫做这条直线的斜率,即 k=tgα(1)若直线1经过 P_1(x_1,y_1)、P_2(x_2,y_2)两点,则直线的斜率公式为 A high school physics class a clear that the first book; from uniform speed motion image can be calculated acceleration. In the velocity image shown in Fig. 1, t 2 -t_1 is denoted by Δt, v_2-v_1 is denoted by Δv, and the slope k of the straight line AB is k = Δv / Δt = a. That is to say, The slope of the velocity graph is equal to the acceleration of the moving object. It can be seen from mathematics that the minimum positive angle formed by the straight line 1 (as shown in FIG. 2) and the positive direction of the x axis is the oblique angle of this straight line. Tilt angle is not a straight line 90 °, the tangential angle of the tangent called the slope of this line, that is k = tgα (1) If the line 1 through P_1 (x_1, y_1), P_2 (x_2, y_2) The slope formula is