数列问题中,我们会碰到由各种各样递推关系给出的数列.求这类数列的通项公式的方法也不少,但其中有一类数列我们经常碰到,这类数列的递推关系为an+1=pan+qrn(p≠1),当r=1时递推关系为an+1=pan+q.这类数列{an}求解的问题可以考查等差 In the sequence of numbers, we encounter the sequence given by the various recursion relations. There are also many ways to find general formulas for such series, but one of them is often encountered The relationship of push is an + 1 = pan + qrn (p ≠ 1). When r = 1, the recursion relation is an + 1 = pan + q. The problems solved by these series {an}