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多题一解是指对众多看似不同的同一类习题采用相同的方法解题．通过这类习题的练习可训练学生的聚敛思维,提高归纳能力,掌握解题规律,以不变应万变．例1 将15．5 g氯酸钾和二氧化锰的混合物加热到质量不再减少为止,剩余固体的质量为10．7g.求: (1)可制得氧气多少克?(2)原混合物中含氯酸钾多少克?(3)剩余固体中含有哪些物质?分别为多少克? 例2 把20 g氧化铜放入试管中通入氢气后加热, 反应一段时间后冷却,称得试管中残余固体物质为 18．4g.求参加反应的氧化铜为多少克? 例3 现有氧化铜和铜粉的混合物4 g,通入足量干燥氢气并加热到质量不再减少为止,冷却后称得剩
More than one solution refers to the same method to solve problems for many seemingly same exercises. Through exercises of this type of exercises, students can be trained in agglomerating thinking, improving their ability to sum up, and mastering the law of problem solving so that they will not change. Example 1 A mixture of 15.5 g of potassium chlorate and manganese dioxide was heated until the mass was no longer reduced. The mass of the remaining solid was 10.7 g. Find: (1) How many grams of oxygen can be produced? (2) The original mixture contains How many grams of potassium chlorate? (3) What are the contents of the remaining solids? How many grams are they? Example 2 Put 20 g of copper oxide into a test tube and heat it with hydrogen gas. After cooling for a certain period of time, obtain the residual solids in the test tube. 18.4g. How many grams of copper oxide is required to participate in the reaction? Example 3 The existing mixture of copper oxide and copper powder is 4 g, and sufficient amount of dry hydrogen gas is introduced and heated until the mass no longer decreases.