论文部分内容阅读
贵刊文［１］通过构造恒等式 ａ２ｂ＋ｃ＋ｂ２ｃ＋ａ＋ｃ２ａ＋ｂ－ａ＋ｂ＋ｃ２ ＝（ａ＋ｂ＋ｃ）（ａｂ＋ｃ＋ｂｃ＋ａ＋ｃａ＋ｂ－３２）巧妙地证明了著名不等式（１）、（２）的等价性：命题１ （１９６３年莫斯科竞赛题）设ａ、ｂ、ｃ∈Ｒ＋，求证： ａｂ＋ｃ＋ｂ?
The article [1] skillfully proves the equivalence of the famous inequalities (1) and (2) by constructing the identity a2b+c+b2c+a+c2a+b-a+b+c2=(a+b+c)(ab+c+bc+a+ca+b-32): Proposition 1 (Moscow Competition of 1963) , b, c∈R+, verification: ab+c+b?