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设a,b,c是△ABC的三边边长,则有如下 Klamkin不等式:a/b+b/c+c/a≥1/3(a+b+c)(1/a+1/b+1/c) (1)文[1]给出了Klamkin不等式的如下逆向形
Let a,b,c be the length of the three sides of △ABC, then there is the following Klamkin inequality: a/b+b/c+c/a≥1/3(a+b+c)(1/a+1/ b+1/c) (1) [1] gives the following inverse of the Klamkin inequality