解应用题往往是按运算顺序列综合算式或列方程求得解决,但有些应用题这样做却比较繁难.对于这类应用题,可以采取逆推法.下面举三个例子说明.例1 A有若干本书,B借走一半加一本,剩下的书C借走一半加两本,再剩下的书,D借走一半加三本,最后A还有两本书,A原有()本书.解设C借书后A剩下x本书,则1/2x-3=2,解得x=10. Solution of application problems are often calculated according to the order of operations or column equations to solve the formula, but some applications are more complicated to do so for this type of problem, you can take the inverse push method. Here are three examples. There are a number of books, B borrow half plus one, the rest of the book C borrow half plus two, and then the rest of the book, D borrow half plus three, the last A there are two books, A original () Book.After the solution to set up C lending x books, 1 / 2x-3 = 2, solution x = 10.