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本刊文 [1 ][2 ]中均谈到把直线l1:A1A12 +B12 x + B1A12 +B12 y +C1A12 +B12 =0 ,l2 :A2A2 2 +B2 2 x + B2A2 2 +B2 2 y +C2A2 2 +B2 2 =0 ,的两方程相加减 ,就得到两直线所成角的平分线方程 .由此联想到 ,如果把两圆O1:x2 + y2 +D1x +E1y +F1=0和O2 :x2 + y2 +D2 x +E2 y +F2
This article talks about the straight line l1: A1A12 +B12 x + B1A12 +B12 y +C1A12 +B12 =0, l2: A2A2 2 +B2 2 x + B2A2 2 +B2 2 y +C2A2 2 + B2 2 = 0 , the two equations are added and subtracted to obtain the bisector equation of the angle formed by the two straight lines. It is thus conceived that if two circles O1: x2 + y2 + D1x + E1y + F1 = 0 and O2 :x2 + y2 +D2 x +E2 y +F2