论文部分内容阅读
本文就极坐标方程求解一些特征量的方法和技巧作一些探索、归纳和总结。方法一:化方程为直角坐标标准方程求解。例1 求曲线5p~2cos20+3p~2-2=0的焦距。分析:本题要求2c,但方程看不出曲线特征,也没给出任何一个特征量。若化方程为p~2=2/3+5cos0,不是极坐标方程的标准形式,难于求解。只好探索,用直角坐标标准方程求解,略解如下。解原方程化为 5p~2(2cos~20-1)+3p~2-2=0
This article makes some explorations, inductions, and summaries on the methods and techniques for solving some feature quantities in polar equations. Method one: The equation is a solution to the Cartesian standard equation. Example 1 Find the focal length of the curve 5p~2cos20+3p~2-2=0. Analysis: This question requires 2c, but the equation does not show the characteristics of the curve, nor does it give any feature. If the chemical equation is p~2=2/3+5cos0, it is not a standard form of the polar equation and it is difficult to solve. Had to explore, solve with the standard equation of Cartesian coordinates, slightly solved as follows. The solution to the original equation is 5p~2(2cos~20-1)+3p~2-2=0