如何求98765432~(23456789)的个位数字?为了解答此类问题,先观察下表: 分析上表,归纳得到以下的几条结论: ①0、1、5、6的任意正整数次幂的个位数字仍分别是0、1、5、6。 ②4、9的任意正整数次幂的个位数字循环出现,循环周期是2.当指数是奇数时,个位数字分别是4、9;当指数是偶数时,个位数字分别是6、1. How to find the digits of 98765432~(23456789)? To answer this kind of question, first look at the following table: Analyze the above table and summarize the following conclusions: 10, 1, 5, and 6 of any positive integer power The digits are still 0, 1, 5, and 6 respectively. The ones digits of any positive integer power of 24, 9 appear in cycles, the cycle is 2. When the exponent is odd, the ones digits are 4, 9; when the exponent is even, the ones digits are 6, 1 respectively. .