我们常用牛顿第二定律求物体的加速度,但若能根据功能关系求出速度的表达式,则应用待定系数法就可求出物体的加速度.下面举例说明这一方法在解题中的运用.例1 如图1所示,两物体的质量分别为 m_1、m_2,m_1>(m_2)/2等,滑轮和细线 We use Newton’s second law to find the acceleration of the object, but if we can find the velocity expression based on the functional relationship, we can use the undetermined coefficient method to find the acceleration of the object. The following example illustrates the application of this method in solving problems. Example 1 As shown in Figure 1, the mass of the two objects is m_1, m_2, m_1> (m_2)/2, etc., pulleys and thin lines