、０．９１８１、０．８９１８＊。例如，果枝始节平均为６的棉株，第２叶有缺刻的比例为４３．８％，第３、４叶缺刻比例均为１００％；而果枝始节平均为９的棉株，第２叶１００％没有缺刻，第３叶有缺刻的仅为６．７％，第４叶为８７．５％。可见，第１片缺刻叶出现早，花芽分化始期早、果枝始节低；反之，则迟、则高。故在幼苗期，棉株有２～３叶时，即可进行早期诊断，以便及时采取促早发措施。３个体、群体果节数的预测大面积、生产上要了解棉花生长动态，特别是蕾花期的个体、群体果节数的发展变化，必须在田间取样株逐株测数，这样费时多、工作量大。现根据棉株花芽分化和现蕾的序列性，推导出单株果节数的计算公式，则省时省工、快速简便。只要已知大田的平均果枝始节和主茎叶数或平均果枝数，即可直接计算，无需每株每个果节查数。公式如下：单株果节数＝［１／４（主茎叶数—果枝始节＋１）２＋１／２（主茎叶数—果枝始节＋１）］·η；或＝［１／４（果枝数）２＋１／２果枝数］·η；求出平均单株果节数，乘以密度即为群体果节量。式中η为校正系数，一般为０．８～１。例如，大田查知平均展叶数为１１．１，果枝始节为６．５，求其单株果节数（η＝０．８５）。代入上式为［１／４（１１? , 0.9181, 0.8918 *. For example, cotton plants with an average fruiting branch length of 6 had 43.8% of the second leaves with notches and 100% of the third and fourth leaves with an average of 9, 100% of the leaves are not nicked, the third leaves are nicked only 6.7%, the fourth leaves are 87.5%. Visible, a lack of early leaves appeared early flower bud differentiation early fruiting branches start low; the other hand, then late, then high. Therefore, seedlings, cotton plants have 2 to 3 leaves, you can make an early diagnosis, in order to promptly take early measures to promote hair growth. 3 individuals, the number of segments of fruit groups forecast a large area, the production to understand the dynamics of cotton growth, especially at the bud stage of the individual, the number of fruit groups development and changes, the strains must be sampled in the field measured by strain, so more time-consuming, work large. Now according to the cotton plant flower bud differentiation and budding sequence, derived the number of fruit nodes per unit of calculation, saving time and labor, quick and easy. As long as the average field known as the beginning of fruiting branches and main stems leaves or the average number of fruit branches, you can calculate directly, without checking the number of fruit nodes per plant. The formula is as follows: the number of fruit nodes per plant = [1/4 (main stem leaf number - fruiting branch start +1) 2 +1/2 (main stem leaf number - fruiting branch start +1)] η; or = [1/4 Number) 2 + 1/2 fruit branch number] · η; find the average number of fruit nodes per plant, multiplied by the density is the number of fruit groups. Where η is the correction factor, usually 0.8 ~ 1. For example, the average number of leaves in field investigation was 11.1, and the number of fruit nodes per plant was 6.5 (η = 0.85). Substituting the above formula for [1/4 (11?