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合成了SnO2-Sb2O3/Ti电极材料.实验结果证实,在14mol/LNaOH水溶液中和完全避免析氧反应的条件下,Fe()物种在该电极上进行电化学氧化并生成FeO2-4.结果表明,Fe(OH)3在浓NaOH溶液中发生酸式电离,形成可溶于水的FeO-2,该离子的浓度随着碱溶液浓度变化而发生明显变化,而且它还是发生化学氧化和电化学氧化的反应物.在SnO2-Sb2O3/Ti电极上,FeO2-4的电化学还原起始电位为0.38V(vs.Hg/HgO,14mol/LNaOH),FeO-2电化学氧化起始电位为0.54V.结果还表明,用电化学方法氧化Fe()物种生成FeO2-4是个多步骤过程.
The SnO2-Sb2O3 / Ti electrode materials were synthesized and the results showed that Fe (superscript 2 +) was electrochemically oxidized and FeO2-4 was formed on the electrode in 14 mol / L NaOH aqueous solution and completely avoiding the oxygen evolution reaction , Fe (OH) 3 acidates in concentrated NaOH solution to form water-soluble FeO-2. The concentration of Fe (OH) 3 changes obviously with the concentration of alkali solution, and it also occurs in chemical oxidation and electrochemical Oxidation reactant. The electrochemical reduction potential of FeO2-4 was 0.38V (vs.Hg / HgO, 14mol / LNaOH) on SnO2-Sb2O3 / Ti electrode. The initial electrochemical oxidation potential of FeO-2was0.54 V. The results also show that the electrochemical oxidation of Fe () species to FeO2-4 is a multi-step process.