求自变量的取值范围是函数概念中的一个重要知识点.有些同学常常会因概念不清而出现错误,下面选择一些同学求解此类问题常出现的错误进行剖析,以期能够引起大家的注意.例1求函数y=(x-2)/(x~2+x-6)的自变量x的取值范围.错解1∵y=(x-2)/(x~2+x-6)=(x-2)/((x+3)(x-2))=1/(x+3).∴函数y=(x-2)/(x~2+x-6)的自变量x的取值范围是x+3≠0,即x≠-3. Find the range of independent variables function concept is an important knowledge point.Some students often because of the concept of unclear and mistakes, following a number of students choose to solve such problems often appear in the analysis, in order to be able to arouse the attention of everyone Example 1 Determine the value range of the argument x for the function y = (x-2) / (x ~ 2 + x-6) (X + 2) / (x + 3) (x-2)) = 1 / (x + 3) The value range of x is x + 3 ≠ 0, that is, x ≠ -3.