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在乙醇溶液中采用快速反应相转移法,分别以n(油溶性茶多酚)∶n(As3+)=2∶1、4∶1、6∶1,pH=4.0,反应温度40~45℃,反应时间15 h的条件,合成了油溶性茶多酚砷,产率59%。配合物的UV为:267.50,218.00,220.50 nm;FTIR为:3 415.6,2 918.6,2 850.2,1 708.2,1 457.3,1 370.4,1 224.2,1 144.0,760.5 cm-1;荧光值,λm ax=257.0,591.1,593.7,590.3,591.0,591.5 nm;XRD,λ为3.697 4,4.186 0,12.076 2,15.474 7 nm1。HNMR,δ=0.782,1.193,1.483~1.586,1.957~2.170,2.479,3.116,3.970~3.981,5.231~5.953,6.537~7.30。确定该配合物为二配位多晶混合物。
In the ethanol solution, the rapid reaction phase transfer method was used. The optimal reaction conditions were as follows: n (As3 +) = 2:1,4:1,6:1 pH = 4.0, reaction temperature 40-45 ℃, Reaction time 15 h conditions, the synthesis of oil-soluble tea polyphenols arsenic, yield 59%. The UV of the complex was 267.50, 218.00, 220.50 nm; FTIR was: 3 415.6, 2 918.6, 2 850.2, 1 708.2, 1 457.3, 1 370.4, 1 224.2, 1 144.0, 760.5 cm-1; = 257.0, 591.1, 593.7, 590.3, 591.0, 591.5 nm; XRD, λ 3.697 4,4.186 0,12.076 2,15.474 7 nm1. HNMR, 6 = 0.782,1.193,1.483-1.586,1.957-2.170,2.479,3.116,3.970-3.981, 5.231-5.953,6.537-7.30. It is confirmed that the complex is a binary coordination polycrystalline mixture.