钟表指针夹角问题看似复杂,但概括起来无外乎两种情形:一是单针转过的角度问题,二是分针、时针夹角问题。只要同学们认真学习,是很容易掌握其解题要领的,下面分别介绍。一、求单针转过角度的方法(单针是指时针或分针)因为时钟上的小格将表盘平均分成60份,每一份(即一小格)对应6 The problem of the angle between the hands of the clocks and watches may seem complicated, but it is no more than a matter of two things: one is the angle of a single needle, and the other is the angle between the minute hand and the hour hand. As long as the students seriously study, it is easy to master the problem-solving essentials. The following are introduced separately. First, find a single needle to turn the angle method (single needle refers to the hour hand or minute hand) because the small grid on the clock divides the dial into 60 equal parts. Each copy (ie a small square) corresponds to 6