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本文根据氮桥系列(Ⅸ)的紫外光谱,应用同系线性规律,定量地证明了在氮桥系列(Ⅸ)中,同系序数N≠m+n+4,因此氮不能同时与芳稠环及烯醛链共轭。紫外谱图的峰形,峰数及代基当量(△N_s)进一步证明了芳稠环与烯醛链互相竞争氮的独对p电子。当芳稠环链的长度m,达到使其竞争力大于烯醛链时,氮主要与芳环共轭,烯醛链只起代基的作用;当烯醛链的长度n,达到使其竞争力大于芳环时,氮则主要与烯醛链共轭,芳环只起代基的作用。随着两边链长m,n的交替增长,则出现竞争共轭的交替现象。
Based on the UV spectrum of the nitrogen bridge series (Ⅸ), the same series of linear rules was used to quantitatively prove that the homologous number N ≠ m + n + 4 in the nitrogen bridge series (IX) Aldehyde chain conjugation. UV spectra of the peak shape, peak number and generation equivalent (△ N_s) further evidence that the aromatic ring and enchain chain competing nitrogen independent p-electron. When the length of the aromatic fused chain reaches its competitiveness greater than that of the enolic chain, the nitrogen is predominantly conjugated to the aromatic ring and the alkene chain functions only as a substituent; when the length of the enalous chain n reaches its competition When the force is greater than the aromatic ring, nitrogen is mainly conjugated with the alkenal chain, the aromatic ring only acting as a substituent. As both sides of the chain m, n alternating growth, there is a competitive conjugate alternating phenomenon.