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荧光素水溶液(浓度1×10~(-4)mol/L,pH 12.5)的荧光能为三乙醇胺(TEOA)所猝灭,其规律符合Stern-Volmer方程。荧光素的单重激发态的猝灭产物,荧光素的还原态,能够在氯铂酸钾(K_2PtCl_6)的存在下还原水产氢。但荧光寿命短(7.0ns),产氢的量子产率只有0.024。四碘荧光素由于有重原子效应,其单重激发态通过系间窜越转变成三重激发态,再和TEOA反应生成还原态去还原水产氢。由于磷光寿命长(～10~(-3)s),产氢的量子产率达0.30。
Fluorescence energy of fluorescein aqueous solution (concentration 1 × 10 -4 mol / L, pH 12.5) was quenched by triethanolamine (TEOA), and its law was in accordance with Stern-Volmer equation. The quenching product of the singlet excited state of fluorescein and the reduced state of fluorescein can reduce hydrogen production in the presence of potassium chloroplatinate (K 2 PtCl 6). However, the fluorescence lifetime is short (7.0ns) and the quantum yield of hydrogen is only 0.024. Tetraiodofluorescein, due to its heavy atom effect, changes its singlet excited state to triplet excited state through intersystem crossing, and reacts with TEOA to generate reduced state to reduce hydrogen production. Due to the long phosphorescence lifetime (~ 10 ~ (-3) s), the quantum yield of hydrogen production reaches 0.30.