某校合唱队里有一个队员病了,临上台表演了,队里的指挥排了一下队伍,如果10人一排,有一排就少1人;如果12人一排,有一排还少1人;如果15人一排,有一排仍少1人.这个合唱队原来一共有多少人?解决这个问题时,先计算出10、12、15三个数的最小公倍数是60.当合唱队中有60个队员时,10人一排、12人一排或15人一排都是正好的.若少1人时,成了59个队员,按上述办法排队时必然都少1人.由此可知,原来合唱队的队员为60人.60是最少可能的人数,其他数太大,不符合现实情况. A school choir team has a player who was ill, came to power on stage, the team’s command line team, if a row of 10, a row less 1; if a row of 12, there is a row less 1 ; If a row of 15 people, there is a row is still less than 1. The total number of the choir originally? To solve this problem, first calculate the least common multiple of 10,12,15 three numbers is 60. When the choir has 60 players, 10 in a row, 12 in a row or 15 in a row are just right. If less than 1, became 59 players, according to the above method will inevitably be less than one line. , The original choir team members of 60. 60 is the minimum number of people, the other number is too large, does not meet the reality.