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1问题的提出求斜率为5的一组平行线被抛物线y二3。‘截得的线段中点轨迹方程。1．l常规解法由已知可设斜率为5的直线方程为y二sx＋b，则直线与抛物线交点坐标为下面方程组的解所以裁得线段的中点坐标为即截得线段中点均在直线6。二5上。因此，斜率为5的平行线被抛物线y二3X‘所
1 PROBLEM PROBLEMS A set of parallel lines with a slope of 5 is parabola y 2 3. 'Intercept of the midpoint trajectory equation. 1. l conventional solution known by setting the slope of 5 for the straight line equation y sx + b, then the intersection point of the straight line and the parabola is the solution of the following system of equations so that the coordinates of the midpoint of the cut line segment is the midpoint of the line segment are in line 6 . Two five on. Therefore, the parallel line with a slope of 5 is parabola y 3X '