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用碱溶法溶出树脂中钼,并借助于钼(Ⅵ)与邻苯三酚红(PR)和溴化十六烷基三甲铵(CTAB)在pH4的溶液中反应形成兰色三元络合物的原理测定钼。测定的最佳条件:络合物光吸收峰值为605纳米,显色酸度为pH2～6,0.03％PR溶液1.4～4毫升,0.2％CTAB溶液1～5毫升。在抗坏血酸、EDTA和氟化铵存在下,下列元素量不干扰10微克钼的测定:0.05毫克Bi~(3+),0.5毫克Al~(3+),0.8毫克Fe~(3+),1毫克UO_2~(2+)、Ca~(2+)、Zn~(2+)、Cu~(2+),2毫克
Molybdenum is eluted from the resin by alkaline dissolution and is reacted with pyrogallol red (PR) and cetyltrimethylammonium bromide (CTAB) in a solution of pH 4 to form a blue ternary complex The principle of determination of molybdenum. The optimal conditions for the determination were as follows: the peak of the light absorption of the complex was 605 nm, the color-developing acidity was pH 2 ~ 6, 1.4 ~ 4 ml of 0.03% PR solution and 1 ~ 5 ml of 0.2% CTAB solution. In the presence of ascorbic acid, EDTA and ammonium fluoride, the following amounts of element do not interfere with the determination of 10 micrograms of molybdenum: 0.05 mg of Bi ~ (3 +), 0.5 mg of Al ~ (3 +), 0.8 mg of Fe ~ (3 + Mg UO_2 ~ (2 +), Ca ~ (2 +), Zn ~ (2 +), Cu ~ (2 +), 2 mg