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使用Cu-ZnO体系催化剂可使CO和H_2在250—300℃和6MPa的温和条件下生成较多的C_2—C_4醇。实验表明,醇的生成是在Cu-ZnO双组份上进行的,产物中C_2—C_(?)醇的含量与催化剂的Cu/Zn比值有关,最佳值是4:5。添加少量K_2O可提高C_2—C_(?)醇的生成量。在K_2O存在下,采用CO:H_2=1:2的原料气,当空速为7000h~(-1)时,液体产物中的C_2-C_(?)醇可达15%。实验结果还表明,催化剂各组份之间有一最佳比值,以Cu:Zn:Al=4:5:1最佳。
Using Cu-ZnO system catalyst, CO and H 2 could generate more C 2 -C 4 alcohols under mild conditions of 250-300 ℃ and 6 MPa. The experiment shows that the alcohol production is carried out on Cu-ZnO bicomponent. The content of C_2-C_ (?) Alcohol in the product is related to the Cu / Zn ratio of the catalyst. The optimum value is 4: 5. Adding a small amount of K 2 O increased the production of C 2 -C_ (?) Alcohol. In the presence of K 2 O, the feed gas with CO: H 2 = 1: 2, when the space velocity is 7000h -1, the C 2 -C_ (?) Alcohol content in the liquid product can reach 15%. The experimental results also show that there is an optimal ratio between the components of the catalyst, Cu: Zn: Al = 4: 5: 1 best.