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最近几年理论计算指出,7He存在几个激发态,甚至有壳模型和量子蒙特卡罗计算预言存在一个低能的、自旋宇称为1/2-的激发态。最近有实验研究指出7He有一低激发能级位于0.6～1.45MeV之间,是基态(3/2-)的自旋劈裂形成的,但是更多的实验和理论计算指出:不存在这一能级,如果其存在,它将预示着远离稳定线核的自旋轨道强度的强烈压低以及在丰中子滴线核处壳模型的完全崩溃。7Li与7He部分能级图的性质如图1所示。7Li*与7He*激发态为同位旋相似态,通过6He+p反应研究7Li*激发态的自旋宇称和衰变分宽度等物理量,进而确定7He*的激发能级和自旋宇称等。
In recent years, theoretical calculations show that there are several excited states in 7He. Even the crustal model and quantum Monte Carlo calculation predict the existence of a low-energy, spin-parity excited state of 1 / 2-. Recent experimental studies have shown that 7He has a low excitation energy level between 0.6 and 1.45 MeV and is formed by spin splitting of the ground state (3 / 2-), but more experimental and theoretical calculations indicate that this energy can not exist If present, it will herald a strong depression of the spin-orbit intensity away from the stable nucleus and a complete collapse of the shell model at the neutron-rich drip line nucleus. 7Li and 7He part of the nature of the energy level diagram shown in Figure 1. The 7Li * and 7He * excited states are isomorphic, and the 7Li * excitation states such as spin parity and decay width are studied by 6He + p reaction to determine the excitation level and spin parity of 7He *.