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一、正用例1已知sinα+cosα=m,sinαcosα=n,则m,n的关系是().A.m=n B.m=2n+1 C.m~2=2n+1 D.m~2=1-2n解将sinα+cosα=m两边平方,得sin~2α+2sinαcosα+cos~2α=m~2,
First, positive use case 1 is known as sinα+cosα=m, sinαcosα=n, then the relationship between m and n is (). Am=n Bm=2n+1 Cm~2=2n+1 Dm~2=1-2n solution Square the sides of sinα+cosα=m to get sin~2α+2sinαcosα+cos~2α=m~2.