有些高考复习资料有这样一个抽象函数题:已知f(x)是2为周期的奇函数,f(-1)= 5,求f(5).题给答案是f(5)=5.现用T为周期的函数的性质f(kT+x)= f(x)(T>0,k∈Z)解答如下:解1 (直接用周期性转化求解): f(5)=f(3×2-1)=f(-1)=5.解2 (先用周期性再用奇偶性): Some college entrance examination review materials have an abstract function title: Known that f (x) is an odd function of 2 cycles, f (-1) = 5, find f (5). The answer to the answer is f (5) = 5. The property of the function T(kT+x)=f(x)(T>0,k∈Z) with T as a function of the cycle is as follows: Solution 1 (solved directly with periodic transformation): f(5)=f( 3 × 2-1) = f (-1) = 5. Solution 2 (first with periodic reuse parity):