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答 :关于钼磷杂多酸还原为钼磷蓝的反应式一般表示为 :(ＮＨ4 ) 3 Ｈ4 [ＰＭｏ2 Ｏ7) 6]+2ＳｎＣｌ2 +4ＨＣｌ (ＮＨ4 ) 3 Ｈ4 [Ｐ(Ｍｏ2 Ｏ5)·5 (Ｍｏ2 Ｏ7) ]+2ＳｎＣｌ4 +2Ｈ2 Ｏ但有报道认为在有ＮａＦ存在下 ,反应中不可能有ＳｎＣｌ4 或ＳｎＣｌ2 - 6的形式
A: The reaction formula for the reduction of molybdophosphoric acid to molybdophosphoric blue is generally expressed as: (NH 4) 3 H 4 [PMo 2 O 7] 6] + 2SnCl 2 + 4HCl (NH 4) 3 H 4 [P (Mo 2 O 5) O7)] + 2SnCl4 + 2H2O However, it has been reported that in the presence of NaF, it is impossible to form SnCl4 or SnCl2 - 6 in the reaction