标题化合物(Ⅰ)经由Mo_4S_4(μ-dtp)_4(Ⅱ)[dtp=S_2P(OEt)_2]和Ni(OAc)_2反应而得。(Ⅰ)晶体属单斜晶系,空间群P2/c,a=13.176(4),b=11.699(3),c=18.526(4)(?),β=116.11(3)°,V=2564(3)(?)~3,Z=2,D_c=1.776g·cm~(-3)。晶体结构由直接法解出,最终偏离因子R=0.085。本文结果表明,可由已知的四核钼簇合物经过配体置换反应,合成得到其簇骼中心[Mo_4S_4]保持不变并具有-OAc作为桥式配体和-dtp作为端基配体的混合配体类立方烷[Mo_4S_4]簇合物。 The title compound (I) is obtained by reacting Mo_4S_4 (μ-dtp) _4 (Ⅱ) [dtp = S_2P (OEt) _2] with Ni (OAc) _2. (Ⅰ) is a monoclinic with space group P2 / c, a = 13.176 (4), b = 11.699 (3), c = 18.526 (4) 2564 (3) (?) ~ 3, Z = 2, D_c = 1.776g · cm ~ (-3). The crystal structure is solved by the direct method with a final deviation factor of R = 0.085. The results show that the known tetranuclear molybdenum clusters can be ligand exchange reaction, the synthesis of the cluster center [Mo_4S_4] remains unchanged with -OAc as a bridge ligand and-dtp as the end ligand Mixed ligand type cubic alkane [Mo_4S_4] cluster.