如何使多个完全平方数中任两数之积被它们的和或差整除,本文加以探究.例1求4个非0完全平方数,使得其中任意两个数的乘积都可以被它们的差整除.解前4个非0完全平方数是1、4、9、16,而16-9=7,16-4=12,16-1=15;9-4=5,9-1=8;4-1=3.7、12、15、5、8、3的最小公倍数是23×3×5×7,令G= How to make the product of any two of the multiple complete square numbers divisible by the sum of their differences, which is explored in this paper.Example 1 Find 4 non-zero perfect square numbers so that the product of any two of them can be their difference Divisor. The first 4 non-0 perfect squares are 1, 4, 9, 16, and 16-9 = 7, 16-4 = 12, 16-1 = 15; 9-4 = 5, 9-1 = 8 ; 4-1 = 3.7,12,15,5,8,3 the least common multiple is 23 × 3 × 5 × 7, so that G =