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目的:对一起食物中毒暴发流行的病原体进行分离鉴定和分子流行病学研究。方法:采集患者和厨工肛拭子、末梢水及物表涂抹拭子共90份。通过分离鉴定、生化试验和血清学试验,确定病原菌后采用实时荧光PCR方法分别检测病原菌毒力基因eaeAi、paHs、tl、ts、tx1与stx2存在情况。其中4株病原菌全基因组经限制性内切酶XbaI酶切后,通过PFGE获得电泳图谱并进行同源性分析。结果:90份标本中22份样品分离出携带eaeA基因的EPEC。BioNumerics分析结果显示4株EPEC PFGE带型完全相同,表明来源于同一克隆株。结论:这起食物中毒是由带eaeA基因非典型EPEC引起的暴发流行。
Objective: To isolate and identify and epidemiological study of pathogens that are common in outbreaks of food poisoning. Methods: A total of 90 samples of swabs were collected from patients and chefs. Through the isolation and identification, biochemical tests and serological tests, the pathogen was identified and the virulence genes eaeAi, paHs, tl, ts, tx1 and stx2 were detected by real-time fluorescence PCR. The whole genome of four pathogens was digested with restriction endonuclease XbaI, and the electrophorogram was obtained by PFGE and the homology analysis was carried out. RESULTS: EECA-carrying EPEC was isolated from 22 of 90 samples. BioNumerics analysis showed that the four EPEC PFGE bands were identical, indicating that they originated from the same clone. Conclusion: This food poisoning is an outbreak that has been caused by atypical EPEC with the eaeA gene.