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(21)题自点 A(-3,3)发出的光线L射到x轴上,被x轴反射,其反射光线所在的直线与圆x~2+y~2-4x-4y+7=O相切,求光线L所在的方程. 为叙述简便计,记反射线所在的直线为L’记已知圆为C,经配方后得而C关于x轴对称圆记为本题的标准答案仅例举两种常见解法,事实上本题的解法很多,是灵活运用代数、几何、三角知识解题的很好例子.可因直线的选择、方法上的选择及直线方程参数选择不同而不同。本文着重强调解法途径选择上
(21) The light from the point A(-3,3) hits the x-axis and is reflected by the x-axis. The line and circle where the reflected light is located is x~2+y~2-4x-4y+7= O tangent, find the equation of the light L. For the sake of simple description, remember that the line on which the reflection line is located is L’, the known circle is C, and after the formula is obtained, C is the standard answer to the x-axis symmetry circle. Two common solutions are cited. In fact, there are many solutions to this problem. They are good examples of using algebra, geometry, and triangular knowledge to solve problems. They can be different because of the choice of the straight line, the choice of method, and the choice of the parameters of the linear equation. This article focuses on the selection of solutions