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以对苯二酚和溴代正丁烷为原料、乙醇和甲苯为溶剂,在碱性条件下,采用相转移催化剂合成二烷氧基对苯乙炔聚合物发光材料的中间体1,4-二丁氧基苯,考察了不同相转移催化剂和反应条件对产品收率的影响。实验结果表明,以双十八烷基甲基胺氯化苄季铵盐(C_(18)H_(37))2N~+MeCH_2PhCl~-为相转移催化剂,在原料配比n(对苯二酚):n(溴代正丁烷)=1:2.2、催化剂用量(基于对苯二酚的物质的量)2.0%、反应温度60℃、反应时间3.0 h的条件下,1,4-二丁氧基苯的收率达93.6%。通过IR和~1H NMR表征,对产品进行了分析和确认。
Hydroquinone and bromine n-butane as raw materials, ethanol and toluene as solvent, under alkaline conditions, the use of phase transfer catalyst synthesis of dialkoxy p-phenylene acetylene polymer luminescent material intermediates 1,4-bis Butoxybenzene, the effects of different phase transfer catalysts and reaction conditions on the yield of products were investigated. The experimental results show that with the dihatadecylmethylamine benzyl chloride (C_ (18) H_ (37)) 2N ~ + MeCH_2PhCl ~ - as the phase transfer catalyst, ): n (brominated n-butane) = 1: 2.2, the amount of catalyst (hydroquinone-based material) 2.0%, the reaction temperature of 60 ℃, the reaction time 3.0 h, The yield of oxybenzene was 93.6%. The product was analyzed and confirmed by IR and 1H NMR.